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CHEMISTRY LEVEL 3


1. GAS LAWS
2. THE MOLE: Formulae and Chemical Equations
3. ORGANIC CHEMISTRY 1
4. NITROGEN AND ITS COMPOUNDS
5. SULPHUR AND ITS COMPOUNDS
6. CHLORINE AND ITS COMPOUNDS
7. A guide to chemical tests based on this module
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Sulphur and its Compounds: Chemical properties of concentrated sulphuric (VI) acid

5.0 Sulphur and its Compounds


5.3.2 Chemical properties of concentrated sulphuric (VI) acid


Oxidation

Sulphuric (VI) acid is obtained from sulphur. Can the acid react with sulphur, "destroying" what produces it? What about magnesium, and even copper which is below hydrogen in the reactivity series? Observe the video demonstration besides Figure 5.3.2(a).


  Reactions of concentrated sulphuric (VI) acid,Sulphur and some of its compounds,  Sulphur and its compounds,high school chemistry

Figure 5.3.2(a): Reactions of concentrated sulphuric (VI) acid


Questions 5.3.2(a)

  1. State and explain, using chemical equations, the observations in each of the four demonstrations (with sulphur, copper, magnesium, and carbon).
  2. Complete the following general word equations for the oxidation of elements by concentrated sulphuric (VI) acid.
    1. Metal + Concentrated sulphuric (VI) acid
    2. Non-metal + Concentrated sulphuric (VI) acid
  3. Give three reasons why concentrated sulphuric (VI) is exceptionally corrosive, attacking metals and non-metals alike.
  4. Which other acid behaves in a similar way as concentrated sulphuric (VI) acid?

Answers to Questions 5.3.2(a)


Dehydration

Watch the video demonstration on the dehydration of cane sugar (C12H22O11) by concentrated sulphuric (VI) acid; then study the pictures in Figure 5.3.2(b).


(courtesy Youtube-Reaction of sugar with concentrated sulfuric acid by Alex)


  Reactions of concentrated sulphuric (VI) acid,Sulphur and some of its compounds,  Sulphur and its compounds,high school chemistry

Figure 5.3.2(b): Dehydration of cane sugar by concentrated sulphuric (VI) acid with cane sugar https://www.youtube.com/watch?v=L0Pl1iGjct4


  1. Hydrated copper (II) sulphate (CuSO4.5H2O)
  2. Cane sugar (C12H22O11)
  3. Ethanol (C2H5OH or CH3CH2OH)
  4. Methanoic acid (HCOOH)
  5. Wood or paper, -(C6H10O5)-n

   Dehydrating property of concentrated sulphuric (VI) acid,Sulphur and some of its compounds,  Sulphur and its compounds,high school chemistry

Figure 5.3.2(c): Dehydrating property of concentrated sulphuric (VI) acid



In dehydration, concentrated sulphuric (VI) acid removes elements of water (H and O) as complete water molecules, nH2O, where n is a whole number. The acid itself remains intact as H2SO4.


Questions 5.3.2(b)

  1. Write the formula and name of each of the products of dehydration Solid G, Gas J, Gas L, Solid M.
  2. Write a complete equation for each of the dehydration reactions (b) to (e) represented in Figure 5.3.2(c). Part (a) is already done below as an example.

  3. CuSO4.5H2O(s) H2SO4(l)→ CuSO4(s) + 5H2O(l)

  4. Identify what looks like white fumes in Figure 5.3.2(b), and explain why it is so thick.
  5. As shown in Figure 5.3.2(c) and the video, a relatively small amount of cane sugar produces a "large quantity" of black solid. Suggest an explanation for this.
  6. Explain why concentrated sulphuric (VI) acid is highly corrosive.
  7. Prepare a brief summary of the oxidation and dehydrating properties of concentrated sulphuric (VI) acid.

Answers to Questions 5.3.2(b)


Concentrated sulphuric (VI) acid has a high affinity for elements of water. It therefore dehydrates and burns virtually all organic materials such as wood, paper, flesh, and cane sugar, charring them first to charcoal, and further to carbon (IV) oxide.